The UV-VIS spectrum of a CH 2 Cl 2 solution of the gold (I) compound shown below with R =


The UV-VIS spectrum of a CH2Cl2 solution of the gold (I) compound shown below with R = Ph is: λmax (ε) = 239 (92500), 269 (67 000), 286 (72 000), 303 (28 000), 315 nm (21000 dm3 mol−1 cm−1).


(a) π* ← π transitions contribute to the observed spectrum. How do these arise? 

(b) Is the compound coloured? 

(c) You are asked to compare the UV-VIS spectra of a series of these compounds with different R substituents. Why should you compare plots of ε against λ rather than A against λ?

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Related Book For  answer-question

Inorganic Chemistry

ISBN: 9781292134147

5th Edition

Authors: Catherine Housecroft

Question Details
Chapter # 4
Section: Problems
Problem: 26
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Question Posted: July 22, 2023 05:37:27