A nucleus of element 112coperniciumis formed using the reaction equation given near the end of Section 11.7.

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A nucleus of element 112—copernicium—is formed using the reaction equation given near the end of Section 11.7. It then undergoes six successive alpha decays. Give the identity of the isotope that results after each step of this process.

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Inquiry into Physics

ISBN: 978-1305959422

8th edition

Authors: Vern J. Ostdiek, Donald J. Bord

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