Question: A MEMS system is undergoing simple harmonic motion according to [ x(t)=left[3.1 sin left(2 times 10^{5} t+0.48 ight)+4.8 cos left(2 times 10^{5} t+1.74 ight) ight]

A MEMS system is undergoing simple harmonic motion according to

\[ x(t)=\left[3.1 \sin \left(2 \times 10^{5} t+0.48\right)+4.8 \cos \left(2 \times 10^{5} t+1.74\right)\right] \mu \mathrm{m} \]

(a) What is the period of motion?

(b) What is the frequency of motion in \(\mathrm{Hz}\) ?

(c) What is the amplitude of motion?

(d) What is the phase and does it lead or lag?

(e) Plot the displacement.

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