Suppose that we wish to implement a dynamic, open-address hash table. Why might we consider the table
Question:
Suppose that we wish to implement a dynamic, open-address hash table. Why might we consider the table to be full when its load factor reaches some value α that is strictly less than 1? Describe briefly how to make insertion into a dynamic, open-address hash table run in such a way that the expected value of the amortized cost per insertion is O(1). Why is the expected value of the actual cost per insertion not necessarily O(1) for all insertions?
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Introduction to Algorithms
ISBN: 978-0262033848
3rd edition
Authors: Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest
Question Posted: