On a Mollier chart, the slope of the curve representing a reversible isobaric process is equal to
Question:
On a Mollier chart, the slope of the curve representing a reversible isobaric process is equal to
(a) \(T-\beta\)
(b) \(T+\frac{1}{\beta}\)
(c) \(T\)
(d) \(\beta T-1\)
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