The 8.25-kV circuit breaker in Table 9.4 can be used for rated fault current interruption of 33
Question:
The 8.25-kV circuit breaker in Table 9.4 can be used for rated fault current interruption of 33 kA at a rated 8.25-kVLL system voltage. Determine the range of system voltage and interruption current it can be used for.
Table 9.4
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Introduction To Electrical Power And Power Electronics
ISBN: 9781466556607
1st Edition
Authors: Mukund R. Patel
Question Posted: