Question: Letting X denote the random variable that is defined as the sum of two fair dice, then In other words, the random variable X can

Letting X denote the random variable that is defined as the sum of two fair dice, then

P{X=2} = P{(1, 1)} = P{X=3} = P{(1, 2), (2, 1)) =

P{X = 4} = P{(1, 3), (2, 2), (3, 1)} = 36

In other words, the random variable X can take on any integral value between 2 and 12 and the probability that it takes on each value is given by Equation 4.1.1. Since X must take on some value, we must have

P{X=5} = P{(1, 4), (2, 3), (3, 2), (4, 1)) = P{X

which is easily verified from Equation 4.1.1.
Another random variable of possible interest in this experiment is the value of the first die. Letting Y denote this random variable, then Y is equally likely to take on any of the values 1 through 6. That is, P{Y = i} = 1/6, i = 1, 2, 3, 4, 5, 6

P{X=2} = P{(1, 1)} = P{X=3} = P{(1, 2), (2, 1)) = P{X = 4} = P{(1, 3), (2, 2), (3, 1)} = 36 P{X=5} = P{(1, 4), (2, 3), (3, 2), (4, 1)) = P{X = 6} = P{(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)} = 36 P{X = 7} = P{(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)} = 36

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