Question: When using generics, what happens if I omit the type argument in either the declaration or the constructor call? begin{tabular}{llll} Stack stack & (=) new
When using generics, what happens if I omit the type argument in either the declaration or the constructor call?
\begin{tabular}{llll}
Stack stack & \(=\) new Stack ()\(;\) & & // unsafe \\
Stack & stack & \(=\) new Stack(); & \(/ /\) unsafe \\
Stack stack & \(=\) new Stack(); & \(/ /\) correct
\end{tabular}
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