Question: Neither Example 4.4 nor Problem 4.73 actually solved the Schrdinger equation for the SternGerlach experiment. In this problem we will see how to set up

Neither Example 4.4 nor Problem 4.73 actually solved the Schrödinger equation for the Stern–Gerlach experiment. In this problem we will see how to set up that calculation. The Hamiltonian for a neutral, spin- 1/2 particle traveling through a Stern–Gerlach device is

H = p 2m - YB. S

where B is given by Equation 4.169. The most general wave function for a spin- 1/2 particle—including both spatial and spin degrees of freedom—is
(a) Put Ψ (r, t) into the Schrödinger equation

to obtain a pair of coupled equations for Ψ±. 

(b) We know from Example 4.3 that the spin will precess in a uniform field B0k̂. We can factor this behavior out of our solution—with no loss of generality—by writing

Find the coupled equations for Ψ̅±.

(c) If one ignores the oscillatory term in the solution to (b)—on the grounds that it averages to zero (see discussion in Example 4.4)—one obtains uncoupled equations of the form

Based upon the motion you would expect for a particle in the “potential” V±, explain the Stern–Gerlach experiment.

Example 4.4

H = p 2m - YB. S

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