Question: Using a trial function of your own devising, obtain an upper bound on the ground state energy for the bouncing ball potential (Equation 2.185), and

Using a trial function of your own devising, obtain an upper bound on the ground state energy for the “bouncing ball” potential (Equation 2.185), and compare it with the exact answer (problem 2.59):

Egs = 2.33811 (mgh/2)1/3.

Egs = 2.33811 (mgh/2)1/3.

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The trial function has to vanish at x 0 and of course go to zero at Ill choose We firs... View full answer

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