Two graphs (G_{1}=left(V_{1}, E_{1} ight)) and (G_{2}=left(V_{2}, E_{2} ight)) are called isomorphic if there is a one-to-one onto function (f: V_{1} ightarrow V_{2}) such

Two graphs \(G_{1}=\left(V_{1}, E_{1}\right)\) and \(G_{2}=\left(V_{2}, E_{2}\right)\) are called isomorphic if there is a one-to-one onto function \(f: V_{1} \rightarrow V_{2}\) such that for all \(v, w \in V_{1}\) edge \((v, w) \in E_{1}\) if and only if edge \((f(v), f(w)) \in E_{2}\). Show that the two directed graphs below cannot be isomorphic.