Suppose the experimental rate law for the reaction X 2 + Y 2 2 XY is:
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Suppose the experimental rate law for the reaction X2 + Y2 → 2 XY is: Rate = k[X2][Y2] A student postulates a multistep mechanism in which the first step is the rate-determining step. For this step, he postulates 2Y2 → Y3 + Y. Is it possible for this to be the rate-determining step?
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No In any multistep mechanism the rate law for ...View the full answer
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Related Book For 
Introductory Chemistry Atoms First
ISBN: 9780321927118
5th Edition
Authors: Steve Russo And Michael Silver
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