What volume of 0.150 M barium hydroxide is required to neutralize 1.655 g of potassium hydrogen phthalate,

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What volume of 0.150 M barium hydroxide is required to neutralize 1.655 g of potassium hydrogen phthalate, KHC8H4O4 (204.23 g/mol)? 

2 KHC8H4O4(aq) + Ba(OH)2(aq) → BaK2(C8H4O4)2(aq) + 2 H2O(l)

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