What volume of 0.128 M calcium hydroxide is required to neutralize 1.466 g of potassium hydrogen phthalate,

Question:

What volume of 0.128 M calcium hydroxide is required to neutralize 1.466 g of potassium hydrogen phthalate, KHC8H4O4 (204.23 g/mol)? 

2 KHC8H4O4(aq) + Ca(OH)2(aq) → CaK2(C8H4O4)2(aq) + 2 H2O(l)

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: