What will be the result of compiling and running the following program?

Select the one correct answer.

(a) The code will fail to compile, since x[0]++; is not a legal statement.

(b) The code will compile and will print a=1 b=1 bArr[0]=1 at runtime.

(c) The code will compile and will print a=0 b=1 bArr[0]=1 at runtime.

(d) The code will compile and will print a=0 b=0 bArr[0]=1 at runtime.

(e) The code will compile and will print a=0 b=0 bArr[0]=0 at runtime.

public class Passing { public static void main (String[] args) { int a = 0; int b= 0; int [] bArr= new int [1]; bArr [0] inc1(a); inc2 (bArr); } } = b; System.out.println ("a=" + a + " b=" + b + "bArr [0]=" +bArr [0]); public static void incl (int x) { x++; } public static void inc2 (int [] x) { x[0] ++; }