A forced harmonic oscillator with a circular frequency 6 283 s 1 (frequency 1 000 s 1 ) is exposed to an external force F 0 sin (t) with circular frequency 7 540 s 1 such that in the solution of Eq (12 63) becomes z(t) sin(t) 0 100 sin (t) Using Excel or Mathematica, make a graph of z(t) for a time...

A forced harmonic oscillator with a circular frequency = 6.283 s 1 (frequency = 1.000

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A forced harmonic oscillator with a circular frequency ω = 6.283 s⁻¹ (frequency ν = 1.000 s⁻¹) is exposed to an external force F₀ sin (αt) with circular frequency α = 7.540 s⁻¹ such that in the solution of Eq. (12.63) becomes

z(t) = sin(ωt) + 0.100 sin (αt).

Using Excel or Mathematica, make a graph of z(t) for a time period of at least 20 s.

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Mathematics for Physical Chemistry

ISBN: 978-0124158092

4th Edition

Authors: Robert G. Mortimer

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Question Posted: Dec 29, 2018 10:52 AM

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A forced harmonic oscillator with a circular frequency = 6.283 s 1 (frequency = 1.000

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