Question: Every countable set is a (lambda^{1})-null set. Use the Cantor ternary set (C) (see Problem 7.12) to illustrate that the converse is not true. What

Every countable set is a $\lambda^{1}$-null set. Use the Cantor ternary set $C$ (see Problem 7.12) to illustrate that the converse is not true. What happens if we change $\lambda^{1}$ to $\lambda^{2}$ ?

Data from problem 7.12

Cantor's ternary set. Let (X, )= ([0, 1], [0, 1] (R)), A=A [0,1], and set Co= [0, 1]. Remove the open middle

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