Show that the zero-point energy of a Debye solid composed of (N) atoms is equal to (frac{9}{8}
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Show that the zero-point energy of a Debye solid composed of \(N\) atoms is equal to \(\frac{9}{8} N k \Theta_{D}\).
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Using the Debye spectrum 7415 we have for the zeropoint energy of the solid ...View the full answer
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