Question: An observer with 4-velocity U(vector) measures the properties of a particle with 4-momentum p(vector). The energy she measures is E = p(vector) U(vector) [Eq.

An observer with 4-velocity U(vector) measures the properties of a particle with 4-momentum p(vector). The energy she measures is E = −p(vector) · U(vector) [Eq. (2.29)].


E = - p. . (2.29)


(a) Show that the particle’s rest mass can be expressed in terms of p(vector) as


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(b) Show that the momentum the observer measures has the magnitude


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(c) Show that the ordinary velocity the observer measures has the magnitude


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where |p| and E are given by the above frame-independent expressions.


(d) Show that the ordinary velocity v, thought of as a 4-vector that happens to lie in the observer’s slice of simultaneity, is given by


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E = - p. . (2.29)

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