Question: At low temperatures certain fluids undergo a phase transition to a superfluid state. A good example is 4 He, for which the transition temperature is
At low temperatures certain fluids undergo a phase transition to a superfluid state. A good example is 4He, for which the transition temperature is 2.2 K. As a superfluid has no viscosity, it cannot develop vorticity. How then can it rotate? The answer (e.g., Feynman 1972) is that not all the fluid is in a superfluid state; some of it is normal and can have vorticity. When the fluid rotates, all the vorticity is concentrated in microscopic vortex cores of normal fluid that are parallel to the rotation axis and have quantized circulations Г = h/m, where m is the mass of the atoms and h is Planck’s constant. The fluid external to these vortex cores is irrotational (has vanishing vorticity). These normal fluid vortices may be pinned at the walls of the container.
(a) Explain, using a diagram, how the vorticity of the macroscopic velocity field, averaged over many vortex cores, is twice the mean angular velocity of the fluid.
(b) Make an order-of-magnitude estimate of the spacing between these vortex cores in a beaker of superfluid helium on a turntable rotating at 10 rpm.
(c) Repeat this estimate for a neutron star, which mostly comprises superfluid neutron pairs at the density of nuclear matter and spins with a period of order a millisecond. (The mass of the star is roughly 3 × 1030 kg.)
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a To understand how the vorticity of the macroscopic velocity field is related to the mean angular velocity of the fluid we can consider a simplified diagram Imagine a beaker of superfluid helium with ... View full answer
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