From the Kerr metric (26.70) derive Eqs. (26.84) for the surface area of a spinning black holes
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From the Kerr metric (26.70) derive Eqs. (26.84) for the surface area of a spinning black hole’s horizon—that is, the surface area of the 2dimensional surface {r = r_{H}, t = constant}.
Equations.
Transcribed Image Text:
(26.70a) A *r(!P® = $P)z& +z0Pzd + 2 + ² = 2
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To derive the surface area of a spinning black holes horizon often referred to as the event horizon we start with the Kerr metric 2670 and use the giv...View the full answer
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Modern Classical Physics Optics Fluids Plasmas Elasticity Relativity And Statistical Physics
ISBN: 9780691159027
1st Edition
Authors: Kip S. Thorne, Roger D. Blandford
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