Question: Find dy/dx when y is given by (a) sin(2x + 3) (d) sec 6x (g) xcos x (b) x cos x (e) x tan 2x

Find dy/dx when y is given by

(a) sin(2x + 3) (d) sec 6x (g) xcos x (b) x cos x (e) x tan 2x (h) tan 2x 1 + x sin 2x x + 2 (f) sin 6x (c)

(a) sin(2x + 3) (d) sec 6x (g) xcos x (b) x cos x (e) x tan 2x (h) tan 2x 1 + x sin 2x x + 2 (f) sin 6x (c)

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a Introducing the intermediate variable z 2x 3 we have y sin z and z 2x 3 so by the chain rule dy dy ... View full answer

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