Question: Points A, B, C have coordinates (1, 2, 1), (1, 1, 3) and (2, 2, 2) respectively. Calculate the vector product AB(vector) AC(vector),

Points A, B, C have coordinates (1, 2, 1), (–1, 1, 3) and (–2, –2, –2) respectively. Calculate the vector product AB(vector) × AC(vector), the angle BAC and a unit vector perpendicular to the plane containing A, B and c. Hence obtain

(a) The equation of the plane ABC;

(b) The equation of a second plane, parallel to ABC, and containing the point D(1, 1, 1);

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a b c AB 2 1 2 and AC 343 so j k AB X AC 2 ... View full answer

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