Question: Show that the function g(x) = [H(x a) H(x b)] f(x), a In other words, g(x) is a function that is identical

Show that the function g(x) = [H(x – a) – H(x – b)] f(x), a

0 g(x)=f(x) 0 (x < a) (ax b) (x = b)

In other words, g(x) is a function that is identical to the function f(x) in the interval [a, b] and zero elsewhere. Hence express as simply as possible in terms of Heaviside functions the function defined by

f(x) = (0 ax 1 a(21 - x) 1 (x < 0) (0 x1) (1  x  21) (x > 21)

0 g(x)=f(x) 0 (x < a) (ax b) (x = b)

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