Show that the vector a which satisfies the vector equation must take the form a = (,
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Show that the vector a which satisfies the vector equation
must take the form a = (α, 2α –1, 1). If in addition the vector a makes an angle cos−1(1/3) with the vector (i – j + k) show that there are now two such vectors that satisfy both conditions.
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The corresponding points are a 1 1 1 and 5 11 ...View the full answer
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