Question: Solve the differential equation subject to the initial conditions x = dx/dt = 1 and d 2 x/dt 2 = 0 at t = 0.

Solve the differential equation

dx dt3 dx +5- dt dx + 17 +13x = 1 (t > 0) dt

subject to the initial conditions x = dx/dt = 1 and d2x/dt2 = 0 at t = 0.

dx dt3 dx +5- dt dx + 17 +13x = 1 (t > 0) dt

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