Question: Solve the differential equation subject to the initial conditions x = 1 and dx/dt = 0 at t = 0. dx dt dx + 5

Solve the differential equation

dx dt dx + 5 + 6x = 2e (t > 0) dt

subject to the initial conditions x = 1 and dx/dt = 0 at t = 0.

dx dt dx + 5 + 6x = 2e (t > 0) dt

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Taking Laplace transforms dx dt leads to the transformed equation dx 5L 6Lx 2Le dr sXs sx0 t0 5... View full answer

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