Question: Show that a variational calculation with a BCS wavefunction as the variational state, where (hat{H}) is the Hamiltonian and (lambda) is the variational parameter, leads
Show that a variational calculation with a BCS wavefunction as the variational state,
where \(\hat{H}\) is the Hamiltonian and \(\lambda\) is the variational parameter, leads to \(\lambda=d E / d N\), where \(E\) is the energy and \(N\) is the average particle number.
8(BCS ABCS) = (BCS| ' |BCS) = 0,
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