Consider the differential equation y = y 2 subject to y(0) = 2. (a) What is the
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Consider the differential equation y′ = y2 subject to y(0) = 2.
(a) What is the value of y from the predictor–corrector scheme after a single step h = 1/4?
(b) It is easy to show that the exact value at x = 1/4 is y = 4. Based on your result for a step size h = 1/4, what step size do we need to reduce the error (defined as |ynumerical − yexact|) to a value of 1/8?
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Numerical Methods With Chemical Engineering Applications
ISBN: 9781107135116
1st Edition
Authors: Kevin D. Dorfman, Prodromos Daoutidis
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