Question: Show that where α 0, b 0, and α and b are positive integers. [7.44] sin akx cos bkx dx = 0 [7.45] 8 cos

Show that

[7.44] sin akx cos bkx dx = 0 [7.45] 8 cos akx cos bkx dx = dab [7.46] dab sin akx sin bkx dx 2

where α ‰  0, b ‰  0, and α and b are positive integers.

[7.44] sin akx cos bkx dx = 0 [7.45] 8 cos akx cos bkx dx = dab [7.46] dab sin akx sin bkx dx 2

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