The transmittance of a real linear polarizer illuminated by linear light making an angle of Icirc cedil with its transmission axis is given by T l (T 0 T 90 ) cos 2 Icirc cedil T 90 where T 0 and T 90 are the maximum and minimum values of transmittance, respectively Show that this expression is equ...

The transmittance of a real linear polarizer illuminated by linear light making an angle of Î¸ with

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The transmittance of a real linear polarizer illuminated by linear light making an angle of Î¸ with its transmission axis is given by

T_l = (T₀ - T₉₀) cos ²Î¸ + T₉₀

where T₀ and T₉₀ are the maximum and minimum values of transmittance, respectively. Show that this expression is equivalent to Eq. (8.25).

T¡ = T, cos 0 + T90 sin² 0 (8.25)

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Optics

ISBN: 978-0133977226

5th edition

Authors: Eugene Hecht

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Question Posted: Jan 10, 2019 11:50 AM

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The transmittance of a real linear polarizer illuminated by linear light making an angle of Î¸ with

Question:

T¡ = T, cos 0 + T90 sin² 0 (8.25)

Step by Step Answer:

T ToT cos 0 To 90 ...View the full answer

Optics

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