A compound forms cis-1,2-dimethycyclopropane when it is reduced with H 2 and Pd/C. The 1 H NMR
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A compound forms cis-1,2-dimethycyclopropane when it is reduced with H2 and Pd/C. The 1H NMR spectrum of the compound shows only two singlets. What is the structure of the compound?
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As we know H 2 and Pt C is reductive catalyst which did the reduction of the double bond to single b...View the full answer
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