When methyl alcohol is treated with NaH, the product is CH 3 O - Na + (and
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When methyl alcohol is treated with NaH, the product is CH3O-Na+ (and H2) and not Na+ -CH2OH (and H2). Explain why this is so.
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The proton of the OH group is acidic in nature as it is attached to a highly electronegative el...View the full answer
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Related Book For 
Organic Chemistry
ISBN: 978-1118133576
11th edition
Authors: Graham Solomons, Craig Fryhle, Scott Snyder
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