If a solution of fluorescein at pH = 9 is subjected to visible light at 488 nm,

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If a solution of fluorescein at pH = 9 is subjected to visible light at 488 nm, it has maximum fluorescence at 510 nm. Calculate the energy difference between the absorbed and fluorescing radiation in kJ mol^–1.

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Organic Chemistry

ISBN: 9781936221349

6th Edition

Authors: Marc Loudon, Jim Parise

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Question Posted: Dec 03, 2023 04:48 AM

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If a solution of fluorescein at pH = 9 is subjected to visible light at 488 nm,

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To calculate the energy difference between the absorbed and fluorescing radiation we can use the fol...View the full answer

Organic Chemistry

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