Question: 8. The decision rule for testing the null hypothesis that an effect is zero against the alternative hypothesis that the effect is nonzero is reject
8. The decision rule for testing the null hypothesis that an effect is zero against the alternative hypothesis that the effect is nonzero is reject H0 if ss/ν ssE/df = ms msE > Fν,df,α , where ss is the sum of squares calculated in rule 4, ν is the degrees of freedom in rule 2, and ms = ss/ν. Example : To test HABD 0 : {the interaction ABD is negligible} against HABD A : {the interaction ABD is not negligible}, the decision rule is reject HABD 0 if ms(ABD) msE > F(a−1)(b−1)(d−1),df,α.
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