Question: A (0.25-mathrm{kg}) bob is suspended from a string that is (0.60 mathrm{~m}) long. When the pendulum is set into small-amplitude oscillation, the amplitude decays to
A \(0.25-\mathrm{kg}\) bob is suspended from a string that is \(0.60 \mathrm{~m}\) long. When the pendulum is set into small-amplitude oscillation, the amplitude decays to half of its initial value in \(35 \mathrm{~s}\).
(a) What is the time constant \(\tau\) for the pendulum?
(b) At what instant is the energy half of its initial value?
Step by Step Solution
3.55 Rating (148 Votes )
There are 3 Steps involved in it
To solve this problem well use the equation for the decay of amplitude in a damped harmonic oscillat... View full answer
Get step-by-step solutions from verified subject matter experts
