A block of mass (m=0.50 mathrm{~kg}) is suspended from a spring of spring constant (k=100 mathrm{~N} /

Question:

A block of mass \(m=0.50 \mathrm{~kg}\) is suspended from a spring of spring constant \(k=100 \mathrm{~N} / \mathrm{m}\).

(a) How far below the end of the relaxed spring at \(x_{0}\) is the equilibrium position \(x_{\mathrm{eq}}\) of the suspended block (Figure 15.29a)?

(b) Is the frequency \(f\) with which the block oscillates about this equilibrium position \(x_{\text {eq }}\) greater than, smaller than, or equal to that of an identical system that oscillates horizontally about \(x_{0}\) on a surface for which friction can be ignored (Figure 15.29b)?

Data from Figure 15.29b

image text in transcribed

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: