Question: A parallel-plate capacitor initially has capacitance (C). The distance between the plates is then doubled, with a (9.0-mathrm{V}) battery connected. The battery is then disconnected,

A parallel-plate capacitor initially has capacitance $C$. The distance between the plates is then doubled, with a $9.0-\mathrm{V}$ battery connected. The battery is then disconnected, and the plate area is doubled. Finally, a $20-\mathrm{V}$ battery is connected across the plates. What is the new capacitance?

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