Question: A parallel-plate capacitor of capacitance (10 mu mathrm{F}) is being charged by a voltage source (V=V_{0} cos (omega t)). Suppose that (V_{0}=240 mathrm{~V}) and (omega=50

A parallel-plate capacitor of capacitance $10 \mu \mathrm{F}$ is being charged by a voltage source $V=V_{0} \cos (\omega t)$. Suppose that $V_{0}=240 \mathrm{~V}$ and $\omega=50 \mathrm{~s}^{-1}$.

(a) What is the maximum displacement current through a cross-sectional area inside the capacitor that is half the area of each plate?

(b) How would this area have to be oriented relative to the electric field to get this maximum displacement current?

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