An object resting on a table oscillates on the end of a horizontal spring. Because the table is covered with a viscous substance, the motion is damped and the amplitude gets smaller with each cycle. At \(t=1.5 \mathrm{~s}\), the object is \(60 \mathrm{~mm}\) from its equilibrium position, and this is the farthest from equilibrium it reaches. The amplitude of the next cycle of the motion is \(56 \mathrm{~mm}\), and the object reaches this maximum \(x\) value at \(t=2.5 \mathrm{~s}\). Write the equation for the object's \(x\) component of position as a function of time, using numerical values for all constants.