Question: Calculated using the value (g=9.8 mathrm{~m} / mathrm{s}^{2}), the time interval required for an object released from rest at some arbitrary point (mathrm{A}) above the

Calculated using the value $g=9.8 \mathrm{~m} / \mathrm{s}^{2}$, the time interval required for an object released from rest at some arbitrary point $\mathrm{A}$ above the ground to reach the ground is $\Delta t$. If $g$ were $4.9 \mathrm{~m} / \mathrm{s}^{2}$, by what factor would $\Delta t$ differ from the value calculated using $g=9.8 \mathrm{~m} / \mathrm{s}^{2}$ ?

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