Question: Express the Bragg condition (2 d cos theta=m lambda) in terms of the Bragg angle (alpha) between the (mathrm{x}) rays and the surface of the

Express the Bragg condition $2 d \cos \theta=m \lambda$ in terms of the Bragg angle $\alpha$ between the $\mathrm{x}$ rays and the surface of the sample rather than the angle $\theta$ between the $\mathrm{x}$ rays and the surface normal.

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