Question: The force exerted on a certain object varies with the object's position according to the function (F_{x}(x)=a x^{2}+b x^{3}) where (a=3.0 mathrm{~N} / mathrm{m}^{2}) and

The force exerted on a certain object varies with the object's position according to the function \(F_{x}(x)=a x^{2}+b x^{3}\) where \(a=3.0 \mathrm{~N} / \mathrm{m}^{2}\) and \(b=-0.50 \mathrm{~N} / \mathrm{m}^{3}\). What is the work done on the object by this force as the object moves from \(x=-0.40 \mathrm{~m}\) to \(x=2.0 \mathrm{~m}\) ?

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