Two (1.00-mathrm{kg}) spheres carry identical charges and are placed a distance (d) from each other. (a) How

Question:

Two \(1.00-\mathrm{kg}\) spheres carry identical charges and are placed a distance \(d\) from each other.

(a) How large should the charge on each sphere be so that the repulsive electric force between them balances the attractive gravitational force between them? 

\((b)\) What is the smallest mass that can balance in this way, given that the smallest possible charge is \(e=1.602 \times 10^{-19} \mathrm{C}\) ?

(c) Why doesn't the distance between the balls affect this calculation?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: