Question: Two parallel-plate capacitors have the same plate separation. The plate area of capacitor 1 is twice that of capacitor 2. (a) How do the potential

Two parallel-plate capacitors have the same plate separation. The plate area of capacitor 1 is twice that of capacitor 2.

(a) How do the potential differences across the two capacitors compare if the quantity of charge you place on capacitor \(1\left(q_{1}\right)\) is twice the quantity you place on capacitor \(\left(q_{2}\right)\) ?

(b) How do the charge magnitudes on either plate of the two capacitors compare if the potential difference between the plates of capacitor 1 is twice that between the plates of capacitor 2?

Step by Step Solution

3.45 Rating (158 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

Formula for capacitance of a parallelplate capacitor C 0 A d where C the capacit... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Particle Physics Questions!