Question: a. Given that sin 2 /2 = 2 sin , show that 17 sin ( + ) = 1 and state the value of .

a. Given that sin² θ/2 = 2 sin θ, show that √17 sin (θ + α) = 1 and state the value of α.

b. Hence, or otherα = 14.0° b 0°, 151.9°, 360°ise, solve sin²≤ θ ≤ 2 = 2 sin θ for 0 ≤ θ ≤ 360°.

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