N 2 O 3 dissociates according to the equilibrium N 2 O 3 (g) NO 2
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N2O3 dissociates according to the equilibrium N2O3(g) ⇋ NO2(g) + NO(g). At 298 K and one bar pressure, the degree of dissociation defined as the ratio of moles of NO(g) or NO2(g) to the initial moles of the reactant assuming that no dissociatioin occurs is 3.5 × 10−3. Calculate ΔGoR for this reaction.
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We set up the following table We next express K P in terms of n0 eq and P This ...View the full answer
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