Derive Equations (6.12) and (6.13). Equation 6.12 Equation 6.13 F = Fo cos(ot zVoCp/2K) exp(-zVoCp/2K) Fo
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Equation 6.12
Equation 6.13
Transcribed Image Text:
F = Fo cos(ot – zVoCp/2K) exp(-zVoCp/2K) Fo |T = cos(ot — zVоСр/2K — п/4) еxp(-?VоСp/2K).
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Equation 66 shows that so Similarly equation 67 shows that so Thus which is easil...View the full answer
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