Question: An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation
An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is y = 10(ex/20 + e-x/20), -20 ≤ x ≤ 20 where x and y are measured in meters. Find the arc length of the cable between the two towers.

30 10 -20-10 y 10 20 X
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To find the arc length of the cable between the two towers we need to integrate the formula for arc ... View full answer
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