As found in Exercise 39, the centroid of the semicircle y = a 2 - x 2

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As found in Exercise 39, the centroid of the semicircle y = √a2 - x2 lies at the point (0, 2a/π). Find the area of the surface generated by revolving the semicircle about the line y = x - a.


Data from in Exercise 39

Use Pappus’s Theorem for surface area and the fact that the surface area of a sphere of radius a is 4πa2 to find the centroid of the semicircle y = √a2 - x2.

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Thomas Calculus Early Transcendentals

ISBN: 9780321884077

13th Edition

Authors: Joel R Hass, Christopher E Heil, Maurice D Weir

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